The electric field in a region is given by E -2 -3 - - 103 NC -1The electric flux through a rectangular surface 10 cm - 20 cm held parallel to the y-z plance isA- 50 NC -1 m 2B- 40 NC -1 m 2C- 60 NC -1 m 2D- zero

The correct option is B 40 NC^ 1m^2 E_x =2 × 10^3 NC^ 1 and E_y =3 × 10^3 NC^ 1 S=10 cm × 20 cm =200 cm^2 =2 × 10^ 2m^2 The normal to the y z plane is along ...

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Standard XII

Physics

Electric Field

The electric ...

Question

The electric field in a region is given by
$E = (2^i + 3^j) \times 10^{3} N C^{- 1}$
The electric flux through a rectangular surface $10 c m \times 20 c m$ held parallel to the y-z plance is

$40 N C^{- 1} m^{2}$

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$50 N C^{- 1} m^{2}$

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$60 N C^{- 1} m^{2}$

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zero

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Solution

The correct option is A
$40 N C^{- 1} m^{2}$

$E_{x} = 2 \times 10^{3} N C^{- 1}$ and $E_{y} = 3 \times 10^{3} N C^{- 1}$
$S = 10 c m \times 20 c m = 200 c m^{2} = 2 \times 10^{- 2} m^{2}$
The normal to the y-z plane is along the x-axis. Hence Flux $= E_{x} S = 2 \times 10^{3} \times 2 \times 10^{- 2} = 40 N C^{- 1} m^{2}$
Hence the correct choice is (a)

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The electric field in a region is given by
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The electric field in a region is given by E=(2^i+3^j)×103NC−1 The electric flux through a rectangular surface 10cm×20cm held parallel to the y-z plance is

The correct option is A 40NC−1m2 Ex=2×103NC−1 and Ey=3×103NC−1 S=10 cm×20 cm=200 cm2=2×10−2m2 The normal to the y-z plane is along the x-axis. Hence Flux =ExS=2×103×2×10−2=40NC−1m2 Hence the correct choice is (a)

The electric field in a region is given by
$E = (2^i + 3^j) \times 10^{3} N C^{- 1}$
The electric flux through a rectangular surface $10 c m \times 20 c m$ held parallel to the y-z plance is