The electric field in a region is given by E - 35 E0 - with E0-2 - 103 NC-1 Find the flux of this field through a rectangular surface of area 0-2 m2 parallel to the Y-Z plane-

The correct option is B none of theseThe electric flux , ϕ=E⃗. n̂dS Since the surface is parallel to Y Z plane so the normal unit vector will be alo ...

The electric ...

Question

The electric field in a region is given by $\to E = \frac{3}{5} E_{0}^j$ with $E_{0} = 2 \times 10^{3} N C^{- 1}$ Find the flux of this field through a rectangular surface of area $0.2 m^{2}$ parallel to the $Y - Z$ plane.

320 N m^{2} C^{- 1}

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240 N m^{2} C^{- 1}

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400 N m^{2} C^{- 1}

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none of these

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Solution

The correct option is B none of these
The electric flux , $ϕ = \to E .^n d S$
Since the surface is parallel to $Y - Z$ plane so the normal unit vector will be along x-axis i.e $^n =^i$
Thus, $ϕ = (3 / 5) E_{0}^j .^i (0.2) = 0$ (as $^j .^i = 0$ )
Thus, option D will correct.

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The electric field in a region is given by →E=35E0^j with E0=2×103NC−1 Find the flux of this field through a rectangular surface of area 0.2m2 parallel to the Y−Z plane.

The correct option is B none of theseThe electric flux , ϕ=→E.^ndSSince the surface is parallel to Y−Z plane so the normal unit vector will be along x-axis i.e ^n=^iThus, ϕ=(3/5)E0^j.^i(0.2)=0 (as ^j.^i=0)Thus, option D will correct.

The electric field in a region is given by $\to E = \frac{3}{5} E_{0}^j$ with $E_{0} = 2 \times 10^{3} N C^{- 1}$ Find the flux of this field through a rectangular surface of area $0.2 m^{2}$ parallel to the $Y - Z$ plane.

The correct option is B none of these
The electric flux , $ϕ = \to E .^n d S$
Since the surface is parallel to $Y - Z$ plane so the normal unit vector will be along x-axis i.e $^n =^i$
Thus, $ϕ = (3 / 5) E_{0}^j .^i (0.2) = 0$ (as $^j .^i = 0$ )
Thus, option D will correct.