Question

# The electric field in a region is given by →E=35E0 ^i+45E0 ^j with E0=2.0×103NC−1. The flux of this field through a rectangular surface of area 0.2 m2 parallel to the yz-plane is .(Take S.I. system of units everywhere)

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Solution

## The area vector can be written as →A=0.2 ^i( since area is parallel to yz plane) Electric flux ϕ=→E.→A ϕ=[3E05^i+4E05^j].[0.2 ^i] ϕ=0.6E05 ϕ=0.6×2×1035 ϕ=240 Vm

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