The electric field in a region is given by →E=(1200^i+1600^j)N/C. Find the flux of this field through a rectangular surface of area 0.2m2 parallel to the y−z plane.
A
140N-m2/C
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B
440N-m2/C
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C
340N-m2/C
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D
240N-m2/C
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Solution
The correct option is D240N-m2/C Given: →E=(1200^i+1600^j)N/C;
Surface area, A=0.2m2
From the diagram, we can see that positive normal to the rectangular surface area is along +x− axis.