The electric field in a region of space is given by E- - 5i - 2j N-C- The flux of E- due to this field through an area 1m2 lying in the y-z plane- in SI units- is -

The correct option is A 5 The flux , ϕ=E⃗.n̂da=(5î+2ĵ).î(1)=5 as area y z plane so normal vector is along x direction. ...

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Standard XII

Physics

Introducing Flux

The electric ...

Question

The electric field in a region of space is given by $\to E = 5 ˆ i + 2 ˆ j N / C$ . The flux of $\to E$ due to this field through an area $1 m^{2}$ lying in the y-z plane, in SI units, is :

5

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5 \sqrt{29}

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Solution

The correct option is A $5$
The flux , $ϕ = \to E .^n d a = (5^i + 2^j) .^i (1) = 5$ as area y-z plane so normal vector is along x direction.

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The electric field in a region of space is given by →E=5ˆi+2ˆj N/C. The flux of →E due to this field through an area 1m2 lying in the y-z plane, in SI units, is :

The correct option is A 5The flux , ϕ=→E.^nda=(5^i+2^j).^i(1)=5 as area y-z plane so normal vector is along x direction.

The electric field in a region of space is given by $\to E = 5 ˆ i + 2 ˆ j N / C$ . The flux of $\to E$ due to this field through an area $1 m^{2}$ lying in the y-z plane, in SI units, is :

The correct option is A $5$
The flux , $ϕ = \to E .^n d a = (5^i + 2^j) .^i (1) = 5$ as area y-z plane so normal vector is along x direction.