The electric field in a region of space is given by →E=E0^i+2Eo^j where Eo=100N/C. The flux of this field through a circular surface of radius 0.02 m parallel to the Y-Z plane is nearly :
A
0.125Nm2/C
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B
0.02Nm2/C
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C
0.005Nm2/C
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D
3.14Nm2/C
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Solution
The correct option is A0.125Nm2/C Answer is A. We know that, ϕ=E.ACosθ . Since surface area is parallel to Y-Z plane therefore, y component of electric field will not contribute to flux through the circular surface. So, ϕ=πr2Eo=3.14×0.0004×100=0.125Nm2/C