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Question

The electric field in an electromagnetic wave is given by E=(50 NC1)sin ω(txc).
Find the electrical energy contained in a cylinder of cross-section 10 cm2 and length 50 cm along the x-axis.

A
5.5×1012J
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B
1.1×108J
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C
5×104J
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D
1.1×1012J
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Solution

The correct option is A 5.5×1012J
Given that
E=(50 NC1)sin ω(txc)
E0=50 NC1A=10 cm2L=50 cm
Now we know energy density is given by
UD=12ε0E20
UD=12×8.85×1012×502
UD=1.1×108 J/m3
So energy contained can be obtained by
UT=UD×V
where V is the volume
UT=UD×A×L
UT=1.1×108×50×10×104
UT=5.5×1012 J


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