The electric field of light wave is given as →E=103cos(2πx5×10−7−2π×6×1014t)^xNC
This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is
Given, E(ineV)=12375λ(inÅ)
A
2.48 V
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B
0.72 V
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C
0.48 V
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D
2.0 V
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Solution
The correct option is C0.48 V Given: ω=2π×6×1014 ⇒f=6×1014Hz