The electric field vector at any cross-section of a conductor and the current density vector both have the same direction

True

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False

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Solution

The correct option is A True
Yep! That’s true
You see $\to E = \frac{m}{n e^{2} τ} \to J$ and the coefficient of $\to J$ are positive so $\to E$ and $\to J$ are in the same direction.

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The electric field vector at any cross-section of a conductor and the current density vector both have the same direction

The correct option is A TrueYep! That’s true You see →E=mne2τ→J and the coefficient of →J are positive so →E and →J are in the same direction.

The correct option is A True
Yep! That’s true
You see $\to E = \frac{m}{n e^{2} τ} \to J$ and the coefficient of $\to J$ are positive so $\to E$ and $\to J$ are in the same direction.