Question

The electric flux through a closed surface is found to be $780N-m^2$ /C Approximately what quantity of charge is enclosed by the surface in nC?

Answer 1

By Gauss's law, the flux through closed surface is $\varphi =\frac{Q_{en}}{{ϵ}_0}$

or $Q_{en}=\varphi {ϵ}_0=780\times (8.85\times {10}^{-12})=6.90\times {10}^{-9}C=6.90nC$