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Gauss's Law

The electric ...

Question

The electric flux through the surface S as due to all the charges as shown in following figure is $\frac{q_{1} + q_{3} - q_{2} - q_{4}}{ϵ_{0}}$

True

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false

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Solution

The correct option is B
false

Clearly the electrical flux due to q₂ and q₄ through the given surface is zero as they lie outside the surface.

$\Rightarrow ϕ = \frac{q_{i n}}{ϵ_{0}} = \frac{q_{1} + q_{s}}{ϵ_{0}}$

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Similar questions

The electric flux through the surface S as due to all the charges as shown in following figure is $\frac{q_{1} + q_{3} - q_{2} - q_{4}}{ϵ_{0}}$

q_{1}

q_{2}

q_{3}

q_{4}

q_{1}

q_{2}

q_{1}

q_{2}

q_{1}, q_{2}, q_{3}

q_{4}

q_{1}, q_{2}, q_{3} a n d q_{4}

(A)

q_{1}, q_{2}, q_{3}

q_{4}

q_{1}

q_{2}

(R)

q_{1}

q_{2}

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