The electric potential in a certain region along the x-axis varies with x according to the relation V(x)=5−4x2. Then, the correct statement is :
V(x)=5−4x2
V(1)=5−4=1V,V(2)=5−4(22)=−11V
Potential difference between x=1m and x=2m is V12=V1−V2=1−(−11)=12V
here, Ex=−dVdx=8x,Ey=−dVdy=0 and Ez=−dVdz=0
The electric force on 1 coulomb charge at x=1 is F=qEx=1(8)=8N