Potential Gradient and Relation between Electric Field and Potential
The electric ...
Question
The electric potential V at any point O (x, y, z all in metres) in space is given by V=4x2 volt. The electric field at the point (1m, 0, 2m) in volt/metre is
A
8 along negative X- axis
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B
8 along positive X - axis
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C
16 along negative X - axis
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D
16 along positive Z - axis
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Solution
The correct option is A 8 along negative X- axis The electric potential V (x,y,z) = 4x2 volt Now →E=−(^i∂V∂x+^j∂V∂y+^k∂V∂z) Now ∂V∂x=8x,∂V∂y=0 and ∂V∂z=0, Hence →E,=−8x^i so at point (1m, 0, 2m) →E=−8^i volt/metre or 8 along negative X-axis