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Electron Affinity

The electron ...

Question

The electron affinity values $(i n k J m o l^{- 1})$ of three halogens x, y and z are respectively -349, -333 and -325. Then x, y and z are respectively

A

F_{2}, C l_{2} a n d B r_{2}

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B

C l_{2}, F_{2} a n d B r_{2}

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C

C l_{2}, B r_{2} a n d F_{2}

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D

B r_{2}, C l_{2} a n d F_{2}

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Solution

The correct option is B $C l_{2}, F_{2} a n d B r_{2}$
Generally electron affinity decreases down the group but $F_{2}$ has a lower electron affinity compared to $C l_{2}$ because the size of $F_{2}$ is very small and hence interelectronic repulsion is high.

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Similar questions

Q. The electron affinity values (kJmol

^{- 1}

) of three halogens

X, Y

Z

respectively are

- 349

- 333

- 325

X, Y

Z

respectively are :

Q. The electron affinity values

(i n k J m o l^{- 1})

of three halogens x, y and z are respectively -349, -333 and -325. Then x, y and z are respectively

Q. Consider the following orders –
(1)

F_{2} > C l_{2} > B r_{2} > I_{2} :

boiling point
(2)

F_{2} > C l_{2} > B r_{2} > I_{2} :

oxidizing nature
(3)

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Acidic nature
(8)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Oxidizing nature
Then calculate

(x^{2} + y^{2})

x

is correct order and

y

is incorrect order.

Q. Increasing oxidising nature of

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

.
if true enter 1, else enter 0.

Q. Bond energy of

F_{2}, C l_{2}

B r_{2}

follow the order:

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