The electron affinity values of elements $A, B, C$ and $D$ are respectively $- 135, - 60, - 200$ and $- 348 k J m o l^{- 1}$ . The outer electronic configuration of element $B$ is:

3 s^{2} 3 p^{5}

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3 s^{2} 3 p^{4}

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3 s^{2} 3 p^{3}

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3 s^{2} 3 p^{2}

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Solution

The correct option is D $3 s^{2} 3 p^{2}$
Since $E_{a}$ increases across the period generally, but exception is at half-filled $p -$ orbital which is stable.
So, ${3 s}^{2} 3 p^{3}$ has less $E_{a}$ among these.

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Similar questions

(i)

2 s^{2} 2 p^{5}

(i i)

3 s^{2} 3 p^{5}

(i i i)

2 s^{2} 2 p^{4}

(i v)

3 s^{2} 3 p^{4}

A

B

1 s^{2}

1 s^{2} 2 s^{2} 2 p^{2}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{4}

3 s^{2} 3 p^{5}

3 s^{1}

4 s^{1}

3 s^{2} 3 p^{5}

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