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Question

The electron with charge (q=1.6×1019 C) moves in an orbit of radius 5×1011 m with a speed of 2.2×106 ms1, around an atom. The equivalent current is:

A
1.12×106 A
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B
1.12×103 A
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C
1.12×109 A
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D
1.12 A
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Solution

The correct option is B 1.12×103 A
Given:
q=1.6×1019 C; r=5×1011 m;v=2.2×106 ms1

As we know that

I=qf=q(v2πr)

putting the given value

I=1.6×1019(2.2×106)(2π)(5×1011)

I=1.12×103 A

Hence, option (b) is correct.
Why this Question ?
The current at time t is
I=limΔt0ΔQΔt=dQdt
Thus, electric current through an area is the rate of transfer of charge from one side of the area to the another.

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