The electronegativity of $H$ and $C l$ are $2.1$ and $3.0$ respectively. The correct statement about the nature of $H C l$ is that it is:

17 %

ionic

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83 %

ionic

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50 %

ionic

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100 %

ionic

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Solution

The correct option is A $17 %$ ionic
Percentage of ionic character $= 16 {(X}_{A} - X_{B}) + 3.5 {(X}_{A} - X_{B})^{2}, = 16 (3 - 2.1) + 3.5 (3 - 2.1)^{2} = 17.235 17 %$
Hence, $H C l$ is $17 %$ ionic.

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