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Standard XII

Chemistry

Chemical Reactivity

The electroni...

Question

The electronic configuration of four elements L, P, Q and R are given in brackets $(1 s^{2}, 2 s^{2} 2 p^{4}); Q (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{5}), p (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{1}); R (1 s^{2} 2 s^{6} 2 p^{6}, 3 s^{2})$ . The formulae of ionic compounds that can be formed between these elements are

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Solution

The correct option is C
L = oxygen; Q = Chlorine; P = Sodium; R = Magnesium

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Similar questions

Q. Electronic configuration of some elements are given below:

L : 1 s^{2} 2 s^{2} 2 p^{4}

Q : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

P : 1 s^{2} 2 s^{2} 2 p^{6}, 3 s^{1}

R : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}

The ionic compound that can be formed by these elements are:

Q. The electronic configuration of four element

L, P, Q

and

R

are given in brackets

L (l s^{2}, 2 S^{2}, 2 p^{4}); P (l s^{2}, 2 s^{2}, 2 P^{6}, 3 s^{1})

Q (l s^{2}, 2 s^{2} 2 P^{6}, 3 s^{2} 3 p^{5})

R (l s^{2}, 2 s^{2} 2 P^{6}, 3 s^{2})

The formulae of ionic compounds that can be formed between these elements are:

Q. The electronics configuration of four element

L, P, Q

and

R

are given in brackets

L (1 s^{2}, 2 s^{2}, 2 p^{4});

Q (1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{5});

P (1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{1});

R (1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2});

The formulae of ionic compound that can be formed between there elements are

Q. Sub-shell electronic configuration of elements P, Q and R is given.
[P, Q and R are imaginary symbols]
P

= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}

,
Q

= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

,
R

= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2} 4 s^{2} 3 d^{1}

(a) One of these electronic configurations given above is wrong. Which is the element?
(b) Out of P, Q and R which has the highest electronegativity?
(c) Can P and Q join to form an ionic compound? Justify your answer.

In the figure, PQRS is a parallelogram with PQ = 16 cm and QR = 10 cm. L is a point Q on PR such that RL: LP = 2:3. QL produced meets RS at M and PS produced at N. Find the lengths of PN and RM.

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The electronic configuration of four elements L, P, Q and R are given in brackets (1s2,2s22p4);Q(1s2,2s22p6,3s23p5),p(1s2,2s22p6,3s1);R(1s22s62p6,3s2). The formulae of ionic compounds that can be formed between these elements are

The correct option is C L = oxygen; Q = Chlorine; P = Sodium; R = Magnesium

The correct option is C
L = oxygen; Q = Chlorine; P = Sodium; R = Magnesium