You visited us 1 times! Enjoying our articles? Unlock Full Access!

Multi-Electron Configurations and Orbital Diagrams

The electroni...

Question

The electronics configuration of four element $L, P, Q$ and $R$ are given in brackets $L (1 s^{2}, 2 s^{2}, 2 p^{4});$ $Q (1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{5});$ $P (1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{1});$ $R (1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2});$

The formulae of ionic compound that can be formed between there elements are

L_{2} P, R L, P Q a n d R_{2} Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

L P, R L, P Q a n d R Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P_{2} L, R L, P Q a n d R Q_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

L P, R_{2} L, P_{2} Q a n d R Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $P_{2} L, R L, P Q a n d R Q_{2}$
correct answer: option 'C'

Valencies of L,Q,Pand R is−2,−1,+1 and +2 respectively so they will form $P_{2} L, R L, P Q a n d R Q_{2}$

Suggest Corrections

Similar questions

(1 s^{2}, 2 s^{2} 2 p^{4}); Q (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{5}), p (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{1}); R (1 s^{2} 2 s^{6} 2 p^{6}, 3 s^{2})

L : 1 s^{2} 2 s^{2} 2 p^{4}

Q : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

P : 1 s^{2} 2 s^{2} 2 p^{6}, 3 s^{1}

R : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}

L, P, Q

R

L (l s^{2}, 2 S^{2}, 2 p^{4}); P (l s^{2}, 2 s^{2}, 2 P^{6}, 3 s^{1})

Q (l s^{2}, 2 s^{2} 2 P^{6}, 3 s^{2} 3 p^{5})

R (l s^{2}, 2 s^{2} 2 P^{6}, 3 s^{2})

L : 1 s^{2} 2 s^{2} 2 p^{4}

Q : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

P : 1 s^{2} 2 s^{2} 2 p^{6}, 3 s^{1}

R : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}

X

Y

X = 2, 8, 2

Y = 2, 8, 7

Join BYJU'S Learning Program