Question

The electronic configurations of four elements are given below. Arrange these elements in the correct order of magnitude (without sign) of their electron affinity.

$\left(i\right)$ $2s^{2}2p^5$
$\left(ii\right)$ $3s^{2}3p^5$
$\left(iii\right)$ $2s^{2}2p^4$
$\left(iv\right)$ $3s^{2}3p^4$

Select the correct answer using the codes given below.

• A. $\left(i\right)<\left(ii\right)<\left(iii\right)<\left(iv\right)$
• B. $\left(iii\right)<\left(iv\right)<\left(i\right)<\left(ii\right)$
• C. $\left(iii\right)<\left(iv\right)<\left(ii\right)<\left(i\right)$
• D. $\left(ii\right)<\left(i\right)<\left(iv\right)<\left(iii\right)$

Answer 1

Answer: (B)

$\left(iii\right)<\left(iv\right)<\left(i\right)<\left(ii\right)$

On the basis of the electronic configuration the corresponding elements are-

$i\left)Fii\right)Cliii\left)Oiv\right)S$

$Cl$ has the highest EA. F should have the highest EA but its size can't accommodate the incoming electron easily because of its small size.

So, $F$ will come second in order. Then, sulfur will come and then oxygen because of the same size reason.

So, the correct option is $B$