Question

The elevator shown in figure is descending, with an acceleration of 2 $m/s^2$. The mass of the block A is 0.5 kg. The force exerted by the block A on the block B is -

• A. 2 N
• B. 4 N
• C. 6 N
• D. 8 N

Answer 1

The correct option is B 4 N

When the elevator in descending apseudo force acts on it in the upword direction

$\therefore$ from free body diagram

$m=0.5$

$g=10$

$a=2$

$mg-N=ma$

$N=m(g-a)$

$=0.5(10-2)=4N$

so the force exerted by the block $Am$ the block $B$ in $4N$