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Question

The elevator shown in figure is descending with an acceleration of 2 ms2. The mass of the block A=0.5 kg. The force exerted by the block A on the block B is (g=10 ms2)

A
2 N
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B
4 N
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C
6 N
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D
8 N
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Solution

The correct option is B 4 N
Drawing FBD of A


Here psuedo force acts upwards as lift is moving downwards with acceleration. a=2 ms2
N+ma=mg
N=0.5(102)=4N

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