The emf of the three galvanic cells: (i) Zn|Zn2+(1M)||Cu2+(1M)|Cu (ii) Zn|Zn2+(0.1M)||Cu2+(1M)|Cu (iii) Zn|Zn2+(1M)||Cu2+(0.1M)|Cu are represented by E1, E2 and E3 respectively. Which of the following is true?
A
E1>E2>E3
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B
E3>E2>E1
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C
E3>E1>E2
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D
E2>E1>E3
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Solution
The correct option is DE2>E1>E3 Zn+Cu2+→Zn2++Cu Ecell=E∘cell−RTnFln[Zn+2][Cu+2]
So higher the value of [Zn+2][Cu+2], lower will be the value of Ecell.