The EMFs of the following cells are Cu|Cu2+(1M)||Ag+(1M)|Ag,Eo=0.46V Zn|Zn2+(1M)||Cu2+(1M)|Cu,Eo=1.10V The EMF of the cell Zn|Zn2+||Ag+(1M)|Ag will be:
A
1.56V
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B
−1.56V
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C
0.64V
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D
2.02V
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Solution
The correct option is A1.56V
According to the question:
Cu|Cu2+(1M)||Ag+(1M)|Ag,Eo=0.46V.....(1) Zn|Zn2+(1M)||Cu2+(1M)|Cu,Eo=1.10V.....(2) Zn|Zn2+||Ag+(1M)|Ag.....(3) From cell (1),[Cu+2Ag+(1M)→Cu2+(1M)+2Ag]−E1o=0.46V From cell (2),[Zn+Cu2+(1M)→Zn2+(1M)+Cu]−E2o=1.10V After adding (1) and (2), we get (3) [Cu+2Ag+(1M)→Cu2+(1M)+2Ag]+[Zn+Cu2+(1M)→Zn2+(1M)+Cu]–––––––––––––––––––––––––––––––––––––––––––––Zn+2Ag+(1M)→Zn2+(1M)+2Ag–––––––––––––––––––––––––––––––––––––––––– Enet=E1o+E2o=0.46V+1.10V=1.56V