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Early History of Organic Compounds

The empirical...

Question

The empirical formula and molecular mass of a compound are $C H_{2} O$ and 180 g respectively. What will be the molecular formula of the compound?

A

C_{9} H_{18} O_{9}

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B

C H_{2} O

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C

C_{6} H_{12} O_{6}

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D

C_{2} H_{4} O_{2}

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Solution

The correct option is C $C_{6} H_{12} O_{6}$
Empirical formula = $C H_{2} O$
Empirical mass $= 12 + 2 + 16 = 30$ g
Molecular mass $= 180$ g
Thus the integral factor is: $n \times E M = M M$
$n \times 30 = 180$
$n = 6$
Molecular formula is $E F_{n}$
$∴ (C H_{2} O)_{6} = C_{6} H_{12} O_{6}$
Hence, option $C$ is correct.

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The empirical formula and molecular mass of a compound are $C H_{2} O$ and 180 g respectively. What will be the molecular formula of the compound ?

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