The empirical formula of a compound is $C H_{2} O$ . Its molecular weight is $180$ . The molecular formula of compound is :

C_{4} H O_{4}

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C_{3} H_{6} O_{3}

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C_{6} H_{12} O_{6}

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C_{5} H_{10} O_{5}

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Solution

The correct option is B $C_{6} H_{12} O_{6}$
Empirical formula weight $= 12 + 2 + 16 = 30$
$n = \frac{180}{30} = 6$
Molecular formula $= (C H_{2} O)_{6} = C_{6} H_{12} O_{6}$ .

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