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Question

The empirical formula of a boron compound is BH3. What will be the molecular formula of the compound if its measured molecular mass is 27.66 g?

A
B3H9
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B
B2H4
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C
B2H6
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D
B3H6
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Solution

The correct option is C B2H6
Given:
Empirical formula of the compound = BH3
Molecular formula
= n x Empirical formula
Thus, n =
Molecular massEmpirical mass
Hence, Empirical mass
= 10.81 + 3 x 1 = 13.81 g
Therefore, n is almost equal 2.
Hence, Molecular formula would be 2(BH3) = B2H6

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