The empirical formula of a compound is $C H_{2} O$ . If 0.0833 moles of the compound contains 1 g of hydrogen, find the molecular formula of the compound.

C_{5} H_{10} O_{5}

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C_{6} H_{12} O_{6}

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C_{4} H_{8} O_{4}

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C_{3} H_{6} O_{3}

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Solution

The correct option is B $C_{6} H_{12} O_{6}$

Empirical formula = $C H_{2} O$
0.0833 moles of a compound contains 1 g of hydrogen atom
So, 1 mol of the compound will contain $\frac{1}{0.0833}$ g $\approx 12$ g of hydrogen atom

Molecular formula = n $\times$ empirical formula
where n is the simple whole number
Mass of hydrogen in molecular formula = 12 g
Mass of hydrogen in empirical formula = 2 g
$∴$ n = 6
MOlecular formula = $(C H_{2} O)_{6}$ = $C_{6} H_{12} O_{6}$

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