The empirical formula of a substance with molar mass $180$ is $C H_{2} O$ . The ratio of molecular formula mass to empirical formula mass is $x : y$ . Then, the value of $x + y$ is :

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Solution

Empirical formula mass of $C H_{2} O = 12 + 2 + 16 = 30$ g.

Molar mass $= 180$ g.

So, $\frac{x}{y} = \frac{180}{30} = \frac{6}{1}$ .

So, $x + y = 6 + 1 = 7$ .

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The empirical formula of a substance with molar mass 180 is CH2O. The ratio of molecular formula mass to empirical formula mass is x:y. Then, the value of x+y is :

Empirical formula mass of CH2O=12+2+16=30g.Molar mass =180g.So, xy=18030=61.So, x+y=6+1=7.

The empirical formula of a substance with molar mass $180$ is $C H_{2} O$ . The ratio of molecular formula mass to empirical formula mass is $x : y$ . Then, the value of $x + y$ is :

Empirical formula mass of $C H_{2} O = 12 + 2 + 16 = 30$ g.

Molar mass $= 180$ g.

So, $\frac{x}{y} = \frac{180}{30} = \frac{6}{1}$ .

So, $x + y = 6 + 1 = 7$ .