The empirical formula of acetic acid is:

C H_{3} - C O O H

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C_{2} H_{4} O

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C H_{2} O

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C H O

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Solution

The correct option is C $C H_{2} O$
The molecular formula of acetic acid is $C H_{3} C O O H$
This contains 2 carbon, 4 hydrogen and 2 oxygen atoms.

$C H_{3} C O O H = C_{2} H_{4} O_{2}$
$C : H : O = 1 : 2 : 1 ⟹ E m p i r i c a l F o r m u l a = C H_{2} O$ .

So, option ( C ) is correct.

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Similar questions

Give the empirical formula of :

(a) Benzene (b) Glucose

{C H}_{3} C O O N a

{C H}_{3} C O O H + {C H}_{3} C O O N a

{C H}_{3} C O O H

C H_{2} O

44

g m o l^{- 1}

C_{2} H_{4} O

The empirical formula of an acid is CH₂O. 0.0835 moles of the compound contains 1g of hydrogen. Molecular formula of the compound is ___

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