Question

The molecular mass of butyric acid was determined by experiment to be 88 $gmo{l}^{-1}$. What is the molecular formula?
Empirical formula=.$C_2{H}_{4}O$

• A. $C_4{H}_8{O}_2$
• B. $C_2{H}_{4}O$
• C. $C{H}_{4}O$
• D. $C_2{H}_4{O}_2$

Answer 1

The correct option is A $C_4{H}_8{O}_2$

Empirical formula mass $=44$
Molecular mass $=88$
we know,
$\frac{\text{Molecular mass}}{\text{Empirical mass}}=\frac{88}{44}=2$
$\therefore \text{Molecular formula =Empirical formula}\times n=C_4{H}_8{O}_2$