The end product $C$ in the following sequence of reaction is:
$C H_{3} B r K C N - -- \to (A) H_{3} O^{+} - -- \to (B) E t h e r - --- \to L i A l H_{4} (C)$

Acetone

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Methane

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Acetaldehyde

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Ethyl alcohol

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Solution

The correct option is D Ethyl alcohol
$C H_{3} B r K C N - -- \to C H_{3} C N (A) H_{3} O^{+} - -- \to C H_{3} C O O H (B) E t h e r - --- \to L i A l H_{4} C H_{3} C H_{2} O H (C)$

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Similar questions

In the following sequence of reactions $C H_{3} - B r K C N \to A H_{3} O^{+} \to B L i A I H_{4} - ---- \to e t h e r C,$ the end product (C) is:

C H_{3} B r K C N - -- \to A H_{3} O^{+} - -- \to B E t h e r - --- \to L i A l H_{4} C

C

C H_{3} B r K C N - -- \to P H_{3} O^{+} - -- \to Q E t h e r - --- \to L i A l H_{4} R

R

C H_{3} C \equiv C H H_{2} S O_{4} / H g^{2 +} - ------- \to H_{2} O / 60^{o} A C H_{3} M g C l - ----- \to H_{2} O B

^{'} C^{'}

C H_{3} C O O H C a C O_{3} - --- \to A H e a t - -- \to B N H_{2} O H - ---- \to C

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