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Electrophilic Substitution Reaction

The end produ...

Question

The end product 'C' of the above reaction is:

P h - C | S H H - C H_{2} - C H_{3}

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P h - C H_{2} - C H_{2} - C H_{2} - S H

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P h - C | | S - C H_{3}

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P h - C H_{2} - C | S H H - C H_{3}

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Solution

The correct option is A $P h - C | S H H - C H_{2} - C H_{3}$

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Similar questions

A g N O_{3}

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

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C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

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C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

A, B

C

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