Question

The energy acquired by a charged particle of $4\mu C$ when it is accelerated through a potential difference of 8 Volt will be :

• A. $3.2\times {10}^{-7}J$
• B. $3.2\times {10}^{-5}J$
• C. $2\times {10}^{-6}J$
• D. $2\times {10}^{-5}J$

Answer 1

Answer: (B)

$3.2\times {10}^{-5}J$

One volt is the potential difference between two points in an electric field such that one joule of work is done in moving one coulomb of charge from one point to another.

So

$W=QV$
$U=4\times {10}^{-6}\times 8=32\times {10}^{-6}=3.2\times {10}^{-5}J$