The energy dissipated by a resistor is 10mJ in 1s when an electric current of 2mA flows through it. The resistance is (inΩ) . (Round off to the Nearest Integer)
Open in App
Solution
Heat dissipated through resistor is given as:H=i2Rt Substituting the values, 10×10−3=(2×10−3)2×R×1 ⇒R=10×1034 ∴R=2500Ω