Question

The energy levels of an atom are as shown here. Which of them will result in the transition of a photon of wavelength $275nm$? which of this transitions corresponds to emissions of radiations of (1)maximum (11)Minimum

Answer 1

Given, wavelength of the photon, $\lambda =275nm$

Energy of the photon is given by,

$E=hv=h\frac{c}{\lambda }=\frac{6.63\times {10}^{-34}\times 3\times {10}^8}{275\times {10}^{-9}\times 1.5\times {10}^{-19}}=4.5eV$

This corresponds to transition B as from the figure.

i) $\Delta E=\frac{hc}{\lambda }\Rightarrow \lambda =\frac{hc}{\Delta E}$

For maximum wavelength should be minimum.

Minimum energy corresponds to transition A.

ii) For minimum wavelength, should be maximum, Maximum energy corresponds to transition D.