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Question
The energy of an electron in the Bohr's first orbit of H-atom is −13.6eV. The possible energy value (s) of the excited state (s) for electrons in Bohr's orbits of hydrogen is (are):
The energy of an electron in the Bohr's first orbit of H-atom is −13.6eV. The possible energy value (s) of the excited state (s) for electrons in Bohr's orbits of hydrogen is (are):
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Solution
The correct option is A −3.4eV
As we know,
E=−13.6×Z2/n2
So, E1 for H=−13.6eV
E2=−13.64=−3.4eV;
E3=−13.69=−1.51;
E4=−13.616=−0.85 and so on.
Hence, the correct option is A
As we know,
E=−13.6×Z2/n2
So, E1 for H=−13.6eV
E2=−13.64=−3.4eV;
E3=−13.69=−1.51;
E4=−13.616=−0.85 and so on.
Hence, the correct option is A
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