Question

# The energy of an electron in the Bohr's first orbit of $$H$$-atom is $$-13.6eV$$. The possible energy value (s) of the excited state (s) for electrons in Bohr's orbits of hydrogen is (are):

A
3.4eV
B
4.2eV
C
6.8eV
D
+6.8eV

Solution

## The correct option is A $$-3.4eV$$As we know,$$E = -13.6\times Z^2/n^2$$ So, $$E_1$$ for $$H=-13.6eV$$$$E_2=\dfrac{-13.6}{4}=-3.4eV$$;$$E_3=\dfrac{-13.6}{9}=-1.51;$$$$E_4=\dfrac{-13.6}{16}=-0.85$$ and so on.Hence, the correct option is $$A$$Chemistry

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