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Question
The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) for the electron in the excited states(s) is (are):
The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) for the electron in the excited states(s) is (are):
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Solution
The correct options are
A -3.40 eV
D -1.51 eV
The energy of an electron on Bohr orbits of hydrogen atoms is given by the expression
En=−13.6 eVn2
where, n takes only integral values.
For the first Bohr orbit n = 1, energy of electron is -13.6 eV.
Apart from that, only -3.4 eV and -1.51 eV can be obtained by substituting n = 2 and n = 3 respectively in the above expression.
As the other options are between -13.6 eV and -1.5 eV, it is not possible for these energy values to have intergral values of n.
A -3.40 eV
D -1.51 eV
The energy of an electron on Bohr orbits of hydrogen atoms is given by the expression
En=−13.6 eVn2
where, n takes only integral values.
For the first Bohr orbit n = 1, energy of electron is -13.6 eV.
Apart from that, only -3.4 eV and -1.51 eV can be obtained by substituting n = 2 and n = 3 respectively in the above expression.
As the other options are between -13.6 eV and -1.5 eV, it is not possible for these energy values to have intergral values of n.
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