1
Question
The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) for the electron in the excited states(s) is (are):
The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) for the electron in the excited states(s) is (are):
Open in App
Solution
The correct option is D -1.51 eV
The energy of an electron on Bohr orbits of hydrogen atoms is given by the expression
En=−13.6 eVn2
where, n takes only integral values.
For the first Bohr orbit n = 1, energy of electron is -13.6 eV.
Apart from that, only -3.4 eV and -1.51 eV can be obtained by substituting n = 2 and n = 3 respectively in the above expression.
As the other options are between -13.6 eV and -1.5 eV, it is not possible for these energy values to have intergral values of n.
The energy of an electron on Bohr orbits of hydrogen atoms is given by the expression
En=−13.6 eVn2
where, n takes only integral values.
For the first Bohr orbit n = 1, energy of electron is -13.6 eV.
Apart from that, only -3.4 eV and -1.51 eV can be obtained by substituting n = 2 and n = 3 respectively in the above expression.
As the other options are between -13.6 eV and -1.5 eV, it is not possible for these energy values to have intergral values of n.
Suggest Corrections
0
Similar questions
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
