Question

The energy of electron in an excited hydrogen atom is -3.4 eV. Its angular momentum according to Bohr's theory will be:

• A. $\frac{h}{\pi }$
• B. $\frac{h}{2\pi }$
• C. $\frac{3h}{2\pi }$
• D. $\frac{2h}{\pi }$

Answer 1

The correct option is A $\frac{h}{\pi }$

$E=\frac{-13.6}{n^2}eV$

$\frac{-13.6}{n^2}=3.4$
$\Rightarrow n=2$

So, its angular momentum $=\frac{nh}{2\pi }$ $=\frac{2h}{2\pi }$ $=\frac{h}{\pi }$