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Bond Order and Enthalpy

the energy of...

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the energy of hydrogen atom in ground state is -13.6eV.its energy correspondent to the quantum number n=5 is

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Q. The energy of hydrogen atom in its ground state is

- 13.5 e V

. The energy of the level corresponding to the quantum number

n = 5

Q. A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. It makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. Then n and Z for this atom will be (Ground state energy of hydrogen atom is – 13.6 eV)

Q. A photon of energy 12.09eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of the excited state is

Q. A hydrogen-like atom of atomic number

Z

is in an excited state of quantum number

2 n

. It can emit a maximum energy photon of

204 e V

. If it makes a transition to quantum state

n

, a photon of energy

40.8 e V

is emitted. Find

n, Z

and the ground state energy (in eV) for this atom. Also, calculate the minimum energy (in eV) that can be emitted by this atom during de-excitation. Ground state energy of hydrogen atom is

- 13.6 e V

.

Q. The energy of hydrogen atom in its ground state is

- 13.6 e V

. The energy of the level corresponding to

n = 5

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