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Standard XII
Physics
Mass Energy Equivalence
the energy of...
Question
the energy of hydrogen atom in ground state is -13.6eV.its energy correspondent to the quantum number n=5 is
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Q.
The energy of hydrogen atom in its ground state is
−
13.5
e
V
. The energy of the level corresponding to the quantum number
n
=
5
is:
Q.
A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. It makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. Then n and Z for this atom will be (Ground state energy of hydrogen atom is – 13.6 eV)
Q.
A photon of energy 12.09eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of the excited state is
Q.
A hydrogen-like atom of atomic number
Z
is in an excited state of quantum number
2
n
. It can emit a maximum energy photon of
204
e
V
. If it makes a transition to quantum state
n
, a photon of energy
40.8
e
V
is emitted. Find
n
,
Z
and the ground state energy (in eV) for this atom. Also, calculate the minimum energy (in eV) that can be emitted by this atom during de-excitation. Ground state energy of hydrogen atom is
−
13.6
e
V
.
Q.
The energy of hydrogen atom in its ground state is
−
13.6
e
V
. The energy of the level corresponding to
n
=
5
is:
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