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Question

The energy released by the fission of one uranium atom is 200MeV. The number of fissions per second required to produce 3.2W of power is (Take, 1eV=1.6×1019J)

A
107
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B
1010
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C
1015
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D
1011
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Solution

The correct option is D 1011

We have the energy released by fission of one uranium atom is 200 Mev.

So, E=200×106×1.6×1019

=3.2×1o11J

The power required =3.2W

Thus the number of fissions required is equal to 3.23.2×1011=1011 fissions.


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