Question

The energy required to remove one neutron from ${}_{13}A{l}^{27}$ is
(given mass of ${}_{13}A{l}^{27}=$26.981541 amu, mass of ${}_{13}A{l}^{26}=$25.984895 amu, mass of neutron $=$ 1.008665 amu)

• A. 6.525MeV
• B. 11.195MeV
• C. 4.232MeV
• D. 8.464MeV

Answer 1

Answer: (B)

11.195MeV

${}_{13}^{27}Al{\to }_{13}^{23}Al{+}^{1}n$
$BE=[25.984895+1.008665-26.981541]\left[931.478\right]MeV$
$=11.195MeV$