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Question

The English alphabet has 5 vowels and 21 consonants. How many words with two different vowels and 2 different consonants can be formed from the alphabet?

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Solution

The English alphabet has 5 vowels and 21 consonants. Since 2 vowels are selected from 5 vowels, thus the number of ways that the vowels are selected is the number of combination of 5 vowels taken 2 at a time.

The formula for combination is,

C n r = n! ( nr )!r!

Substitute 5 for n and 2 for r in the above formula,

C 5 2 = 5! ( 52 )!2! = 5! 3!2!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination becomes,

C 5 2 = 5×4×3! 3!2×1 = 5×4 2×1 =10

Thus the number of ways that the vowels are selected is 10.

Since 2 consonants are selected from 21 consonants, thus the number of ways that the consonants are selected is the number of combination of 21 consonants taken 2 at a time.

The formula for combination is,

C n r = n! ( nr )!r!

Substitute 21 for n and 2 for r in the above formula,

C 21 2 = 21! ( 212 )!2! = 21! 19!2!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination becomes,

C 21 2 = 21×20×19! 19!2×1 = 21×20 2×1 =210

Thus the number of ways that the consonants are selected is 210.

Each combination of 2 vowels and 2 consonants contains 4 letters in total which are also being arranged among them. The number of ways that the 4 letters are arranged is 4! .

The formula to calculate n! is defined as,

n!=1×2×3××( n1 )×n

Thus the factorial of 4 is,

4!=4×3×2×1 =24

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways of selecting 2 vowels and 2 consonants are 10×210×24=50400 .


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