Question

The enol form of acetone, after treatment with $D_{2}O$ gives:

• A. $C{H}_3-\underset{OD}{\underset{|}{C}}=C{H}_2$
• B. $C{H}_3-\underset{O}{\underset{||}{C}}-C{H}_3$
• C. $C{H}_2=\underset{OH}{\underset{|}{C}-}C{H}_{2}D$
• D. $C{D}_2=\underset{OD}{\underset{|}{C}}-C{D}_3$

Answer 1

The correct option is D $C{D}_2=\underset{OD}{\underset{|}{C}}-C{D}_3$

The enol form of acetone, after treatment with $D_{2}O$ gives $C{D}_2=\underset{OD}{\underset{|}{C}}-C{D}_3$. All the H atoms of acetone are exchanged with D atoms during keto enol tautomerism in presence of $D_{2}O$.