Question

The enol from of acetone after treatment with $D_{2}O$ gives:

• A. $C{H}_3-\stackrel{\stackrel{OD}{|}}{C}=C{H}_2$
• B. $C{D}_3-\stackrel{\stackrel{O}{||}}{C}-C{D}_3$
• C. $C{H}_2=\stackrel{\stackrel{OH}{|}}{C}-C{H}_{2}D$
• D. $C{D}_3=\stackrel{\stackrel{OD}{|}}{C}-C{D}_3$

Answer 1

The correct option is A $C{H}_3-\stackrel{\stackrel{OD}{|}}{C}=C{H}_2$

$Me-\stackrel{\stackrel{O}{||}}{C}-C{H}_3\stackrel{Taut.}{\rightleftharpoons }Me-\stackrel{\stackrel{OH}{|}}{C}=C{H}_2\stackrel{D_{2}O}{\to }Me-\stackrel{\stackrel{OD}{|}}{C}=C{H}_2$

$D_{2}O$ exchanges acidic H of (OH) group with D.