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Question

The enthalpies of formation of OH(g), H(g) and O(g) are 21 kJ mol1, 109 kJ mol1and 124 kJ mol1. The value of bond enthalpy OH is

A
424 kJ mol1
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B
212 kJ mol1
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C
424 kJ mol1
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D
212 kJ mol1
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Solution

The correct option is B 212 kJ mol1
The enthalpy of formations of the given gases are :
fH(H,g)=109 kJ mol1
fH(O,g)=124 kJ mol1
fH(OH,g)=21 kJ mol1
We have to calculate H for the equation,
OH(g)H(g)+O(g)
H=fH(H,g)+fH(O,g)fH(OH,g)
H=(109+12421)kJ mol1H=212 kJ mol1

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