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Heat of Formation

The enthalpy ...

Question

The enthalpy change for the reaction, is called:
$2 C_{(g r a p h i t e)} + 3 H_{2} (g) \to C_{2} H_{6} (g)$

A

enthalpy of formation

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B

enthalpy of combustion

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C

enthalpy of hydrogenation

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D

enthalpy of vaporisation

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Solution

The correct option is A enthalpy of formation
Since, the reaction is involving formation of 1 mole of $C_{2} H_{6}$ from its constituent elements $C_{(g r a p h i t e)} and H_{2}$ .
Hence, the given reaction is a formation reaction of $C_{2} H_{6}$ .
Hence, its enthalpy change is enthalpy of formation of $C_{2} H_{6}$ .
Hence, the answer is option $A$ .

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