The enthalpy change for the reaction of 50 mL of ethylene with 50 mL of H2 at 1.5 atm pressure is −0.31 kJ. The value of △U is:
Here the ratio of reactant is 1:1 and product is also forming in ratio of 1.
Therefore, 50 ml of ethylene on reaction with 50 ml of H2 will produce 50 ml. of ethane.
Change in volume is 50ml (ethane)-100ml (C2H4+H2) = 50ml= 0.05L
So,PΔV=−1.5×0.05=0.075Latm≈−7.5 Jolues
Now,
ΔU=ΔH−PΔV=−0.31kJ+7.5J=−302J